​​

B. Magnetic induction

(q)

​​

C. Inductance

(r)

​​

D. Resistance

(s)

​​","answerCount":1,"educationalLevel":"NEET / NCERT","acceptedAnswer":{"@type":"Answer","text":"The correct option is (B\nE): Option (B\nE). Explanation: Correct Answer is:* ​A → s ; B → r ; C → p : D → q​ \n \n\n(A) Energy, $E = \frac{Q^{2}}{2 C}$​​\n\n​$\therefore C = \frac{Q^{2}}{2 E} = \left(J o u l e\right)^{- 1} c o u l o m b^{2}$​​ \n\n(B) Force, _F_ = _Bil_​\n\n​$\therefore B = \frac{F}{i l} = n e w t o n \left(a m p e r e\right)^{- 1} \left(m..."}}}